Here are the sample questions taken from nursingmanthra’s optometric prometric questions :
13. Concave Mirror With Object Between Focus and Centre of Curvature
An object is positioned between the principal focus and the centre of curvature of a concave mirror.
What type of image is formed?
A. Virtual, erect, and diminished
B. Real, inverted, and magnified
C. Virtual, inverted, and magnified
D. Real, erect, and diminished
Answer: B. Real, inverted, and magnified
Rationale: When an object is between the principal focus and centre of curvature of a concave mirror, the image is real, inverted, magnified, and located beyond the centre of curvature.
14. Concave Mirror With Distant Object
An object is placed beyond the centre of curvature of a concave mirror.
Which image is expected?
A. Real, inverted, and diminished
B. Virtual, erect, and magnified
C. Real, erect, and magnified
D. Virtual, inverted, and diminished
Answer: A. Real, inverted, and diminished
Rationale: An object beyond the centre of curvature produces a real, inverted, diminished image between the principal focus and centre of curvature.
15. Convex Mirror
An optometrist uses a convex mirror during an optical demonstration. The object is placed at different distances in front of the mirror.
Which image is consistently produced?
A. Real, inverted, and magnified
B. Virtual, erect, and diminished
C. Real, erect, and diminished
D. Virtual, inverted, and magnified
Answer: B. Virtual, erect, and diminished
Rationale: A convex mirror forms a virtual, erect, laterally inverted, and diminished image for an object placed anywhere in front of it.
16. Total Internal Reflection
During gonioscopy teaching, a trainee asks why the anterior chamber angle cannot be directly visualized through the cornea without a gonioscopy lens.
What is the primary optical reason?
A. Chromatic aberration
B. Total internal reflection
C. Spherical aberration
D. Diffraction at the pupil
Answer: B. Total internal reflection
Rationale: Light originating from the anterior chamber angle is internally reflected at the cornea-air interface. A gonioscopy lens overcomes this effect and permits visualization of the angle.
17. Gonioscopy Lens Refractive Index
Which property of a gonioscopy contact lens allows it to overcome total internal reflection at the corneal surface?
A. A refractive index higher than that of the cornea
B. A refractive index lower than that of air
C. A completely opaque central surface
D. A strongly negative spherical power
Answer: A. A refractive index higher than that of the cornea
Rationale: The source explains that a contact lens with a higher refractive index than the cornea is required to overcome total internal reflection and visualize the anterior chamber angle.
18. Direction of Refraction
A light ray travels from air into the cornea, which is an optically denser medium.
In which direction will the ray bend?
A. Away from the normal
B. Toward the normal
C. Parallel to the interface
D. It will not change direction
Answer: B. Toward the normal
Rationale: When light enters an optically denser medium from a less dense medium, it is refracted toward the normal.
19. Properties Changed During Refraction
A monochromatic light ray passes from air into a transparent lens material.
Which property remains unchanged?
A. Velocity
B. Wavelength
C. Frequency
D. Direction
Answer: C. Frequency
Rationale: During refraction, the velocity and wavelength of light change, and its direction may change. The frequency remains constant as light passes from one medium to another.
20. . Main Refracting Surface of the Eye
A patient asks which ocular structure provides most of the eye’s total refractive power.
Which response is correct?
A. Crystalline lens
B. Cornea
C. Vitreous body
D. Retina
Answer: B. Cornea
Rationale: The source states that the cornea accounts for approximately two-thirds of the eye’s refractive power, while the crystalline lens accounts for approximately one-third.
21. Prism Image Direction
An optometrist places a prism in front of a patient’s eye during diplopia assessment.
In which direction does the patient perceive the image to be displaced?
A. Toward the prism base
B. Toward the prism apex
C. Toward the optical centre
D. Perpendicular to the prism axis
Answer: B. Toward the prism apex
Rationale: Light is deviated toward the base of a prism, but the apparent image is displaced toward the apex. The image remains erect and virtual.
22. Prism Correction for Esotropia
A patient has an 8-prism-dioptre right esotropia causing horizontal diplopia.
Which prism prescription can be used to compensate for the deviation?
A. 8Δ base-in over the right eye
B. 8Δ base-out over the right eye
C. 8Δ base-down over the right eye
D. 4Δ base-in over each eye
Answer: B. 8Δ base-out over the right eye
Rationale: For esotropia, the prism base is positioned opposite the direction of ocular deviation. A base-out prism may be placed before either eye, or the total power may be divided as 4Δ base-out over each eye.
23. Prentice’s Rule Calculation
The optical centre of a +5.00 D spectacle lens is decentered by 10 mm from the patient’s visual axis.
What prismatic effect is induced?
A. 0.5 prism dioptre
B. 2 prism dioptres
C. 5 prism dioptres
D. 10 prism dioptres
Answer: C. 5 prism dioptres
Rationale: Using Prentice’s rule:
Prism power = lens power × decentration in centimetres
Therefore:
5.00 D × 1 cm = 5 prism dioptres.
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